Nilai lim_(θ→π/2)⁡ cos^2⁡ θ/(1-sin ⁡θ)=⋯

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Bahas Soal Matematika   »   Limit   ›  

Nilai \( \displaystyle \lim_{\theta \to \frac{\pi}{2}} \ \frac{\cos^2 \theta}{1 - \sin \theta} = \cdots \)

Pembahasan:

\begin{aligned} \lim_{\theta \to \frac{\pi}{2}} \ \frac{\cos^2 \theta}{1 - \sin \theta} &= \lim_{\theta \to \frac{\pi}{2}} \ \frac{1-\sin^2 \theta}{ 1 - \sin \theta } \\[8pt] &= \lim_{\theta \to \frac{\pi}{2}} \ \frac{ (1+\sin \theta)(1-\sin \theta)}{1-\sin \theta} \\[8pt] &= \lim_{\theta \to \frac{\pi}{2}} \ (1 + \sin \theta)= 1 + \sin \frac{\pi}{2} \\[8pt] &= 1 + 1 = 2 \end{aligned}